TheMatrix
December 4th, 2012, 02:23 AM
Hey guys
I have a lab report that I(and some others, but I'll probably end up doing everything as usual) have to do. Basically, it's about finding a mystery carbonate.
Now while the teacher explained it in class, it makes no sense to me, and I haven't been able to find anything on the internet, either.
I was given 13.81g of "XCO3", where X is the unknown metal. It was narrowed down to the alkali and alkali earth metals, though. And obviously it can't be radioactive.
I was to react that with 2MHCl, which I used 100mL of. Long story short, I needed to find the amount of escaped carbon dioxide, which came out to be 13.99 grams. Some of it may have stayed in the flask, though.
But now I need to figure out what "X" is. Here is the chemical equation I was given and used:
XCO3 + 2MHCl --> CO2 + H2O + XCl2
Of course you have to change that in a simple way for elements not in the first column.
Can anybody explain it to me? I've been thinking about this for days, and nobody around me at school can explain it, either.
Thanks!
I have a lab report that I(and some others, but I'll probably end up doing everything as usual) have to do. Basically, it's about finding a mystery carbonate.
Now while the teacher explained it in class, it makes no sense to me, and I haven't been able to find anything on the internet, either.
I was given 13.81g of "XCO3", where X is the unknown metal. It was narrowed down to the alkali and alkali earth metals, though. And obviously it can't be radioactive.
I was to react that with 2MHCl, which I used 100mL of. Long story short, I needed to find the amount of escaped carbon dioxide, which came out to be 13.99 grams. Some of it may have stayed in the flask, though.
But now I need to figure out what "X" is. Here is the chemical equation I was given and used:
XCO3 + 2MHCl --> CO2 + H2O + XCl2
Of course you have to change that in a simple way for elements not in the first column.
Can anybody explain it to me? I've been thinking about this for days, and nobody around me at school can explain it, either.
Thanks!