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soccer
April 3rd, 2012, 09:07 PM
I cant figure this out for the life of me. Ive been working on the same problem for like an hour. :mad: so here's the problem.

Find the standard form of the equation of the hyperbola given that the foci are (-8,0) and (8,0) and the asymptotes are y=-4x and y=4x

Can any mathematically gifted people help me???

Jess
April 3rd, 2012, 10:02 PM
I'm bad at explaining, and I might be wrong, because it's been a long time since I did hyperbolas...I got some help from here (http://www.purplemath.com/modules/hyperbola3.htm)

if (-8,0) and (8,0) are the foci, then the center is at (0,0)

the slope is a/b = 4/1

a = 4, a^2 = 16
b = 1, b^2 = 1

so the equation would be

(x^2 / 16) - (y^2 / 1) = 1



I'm really sorry if this is the wrong answer. maybe someone who's a much better math expert than me can check this and/or give the right answer if I'm wrong @[email protected]

obsessivedisorder
April 3rd, 2012, 10:13 PM
Oh, lol. I learned this like 2 or 3 months ago and I have now forgotten it again. fml. Or maybe it was first semester, either way it's not good. But, good luck, try khanacadamy.com

Jmihas
April 4th, 2012, 09:10 AM
Do it like a puzzle, I guess.

Jay_Team_Swagg
April 30th, 2012, 10:52 PM
Jess is right

plebble
May 8th, 2012, 02:01 PM
In case you are wondering, on a computer, n^2 just means n squared, n^3 is n cubed, n^4 is n to the power of 4, and so on.